9.1.7 Checkerboard V2 Answers ❲LEGIT – BUNDLE❳

: A helper function often provided in the exercise to format the 2D list into a readable grid in the console.

CodeHS autograders are designed to test understanding, not just completion. If you copy-paste the code above without understanding it, you will struggle on:

def print_board(board): for row in board: # Converts each element to a string and joins them with a space print(" ".join([str(x) for x in row])) # 1. Initialize an empty 8x8 grid with all zeros my_grid = [] for i in range(8): my_grid.append([0] * 8) # 2. Use nested for loops to fill the checkerboard pattern for row in range(8): for col in range(8): # If the sum of indices is even, set the element to 1 if (row + col) % 2 == 0: my_grid[row][col] = 1 # 3. Display the final board print_board(my_grid) Use code with caution. Copied to clipboard Key Components 9.1.7 checkerboard v2 answers

The core challenge is ensuring that every other square is a different color, creating that classic "stair-case" pattern of colors. The Logic Behind the Pattern

The key to this problem is using the modulo operator ( % ) to detect whether a cell should be a 0 or 1. : A helper function often provided in the

: The condition (i + j) % 2 == 0 is the key. →right arrow prints 0 . →right arrow prints 1 .

Tracks the horizontal movement across each row.For every single row, the inner loop runs completely from left to right. 3. Coordinate Calculation Initialize an empty 8x8 grid with all zeros

Employs the (row + col) % 2 == 0 condition to toggle colors.

Diagonal is Row 1, Column 1. Sum: 1 + 1 = 2 (Even) -> Pattern X